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Angles Formed By Intersecting Lines

We are going to study related angles such as side by side angles, linear pair of angles and vertically contrary angles.

Pair of Angles formed by Intersecting Lines

We are going to study related angles such as adjacent angles, linear pair of angles and vertically opposite angles.

one. Adjacent angles

The teacher shows a film of sliced orange with angles marked on it.

Read the conversation between the teacher and students.

Instructor : How many angles are marked on the picture? Can you proper name them?

Kavin : Three angles are marked on the movie. They are AOC, AOB and BOC

Teacher : Which are the angles seen side by side to each other?

Thoorigai : Angles such as AOB and BOC are side by side to each other.

Teacher : How many vertices are at that place?

Mugil : In that location is merely one common vertex.


Teacher : How many arms are at that place? Name them.

Amudhan : In that location are iii arms. They are , OB and

Teacher : Is at that place any common arm for AOB and BOC?

Oviya : Yes.  is the common arm for AOB and BOC .

Teacher : What can you say almost the arms and ?

Kavin : They lie on the either side of the common arm.

Teacher : Are the interiors of AOB and BOC overlapping?

Mugil : No. Their interiors are non overlapping.

Instructor : Hence the two angles, AOB and BOC have one mutual vertex (O), one common arm ( ), other two arms (  and  ) prevarication on either side of the common arm and their interiors do not overlap.

Such pair of angles AOB and BOC are called next angles.

So, 2 angles which have a common vertex and a common arm, whose interiors do not overlap are called adjacent angles .

Now observe the Fig.v.2 in which angles are named 1, 2 and three.

Information technology can exist observed that there are two pairs of adjacent angles such equally ane, 2 and ii, iii. So what nigh the pair of angles one and 3?


They are not adjacent because this pair of angles have a mutual vertex merely they do non accept a mutual arm as two is in betwixt 1 and iii. Besides interiors of one and 3 practice non overlap. Since the pair of angles does not satisfy one amidst the iii conditions they are non adjacent.

Think

In each of the following figures, observe the pair of angles that are marked as 1 and 2. Do you lot recall that they are side by side pairs? Justify your respond.


Endeavour these

1. Few real life examples depicting side by side angles are shown below.


Can y'all requite iii more than examples of adjecent angles seen in real life?


two. Discover the six angles marked in the moving-picture show shown. Write any four pairs of next angles and that are not.


adjacent angles A and B, B and C

C and D, D and Due east

E and F

Not adjacent angles

Aand C

B and D

C and East

Dand F

Aand D

3. Place the mutual arm, common vertex of the side by side angles and shade the interior with two colours in each of the post-obit figures.



4. Name the adjacent angles in each of the following figure.


(i) BAC and CAD

(ii) ZWY and YWX

2. Linear pair

Detect the Fig.5.iii QPR and RPS are adjacent angles. It is articulate that QPR and RPS together volition make QPS which is acute. When QPR and RPS are increased QPS becomes (i) right angle, (two) birdbrained angle, (iii) straight angle and (4) reflex angle as shown in Fig.5.4.



If the resultant angle is a direct angle then the angles are called supplementary angles. The side by side angles that are supplementary lead us to a pair of angles that lie on directly line (Fig.5.4(iii)). This pair of angles are called linear pair of angles.

Try these

ane. Observe the post-obit pictures and find the other angle of linear pair.


The other angle (i) 96° (ii) 94° (three) 21o

Think

Observe the figure. In that location are two angles namely PQR = 150° and QPS = 30°. Is all this pair of supplementary angles a linear pair? Discuss.


Case 5.1 In Fig. 5.5, discover AOC .

Solution


AOC = AOB + BOC

= 46° + 51°

= 97°

Case five.two If POQ = 23° and POR = 62° then find QOR

Solution


We know that POR = POQ + QOR

62° = 23° + QOR

Subtracting 23° on both sides

62° – 23° = 23° + QOR – 23°

QOR = 39°

Instance v.iii Which of the following pair of adjacent angles volition make a linear pair?

(i) 89°, 91° (ii) 105°, 65° (three) 117°, 62° (four) 40°, 140°

Solution

(i) Since 89° + 91° = 180°, this pair will be a linear pair.

(ii) Since 105° + 65° = 170° ≠ 180°, this pair cannot brand a linear pair.

(iii) Since 117° + 62° = 179° ≠ 180°, this pair cannot make a linear pair.

(iv) Since 40° + 140° = 180°, this pair will exist a linear pair.

Instance five.iv Find the missing angle.


Solution

(i) Since the angles are linear pair,

ACD + BCD = 180°

 123° + BCD = 180°

Subtracting 123° on both sides

123° + BCD – 123° = 180° – 123°

BCD = 57°

(ii) Since the angles are linear pair, LNO + MNO = 180°

46° + MNO = 180°

Subtracting 46° on both sides

46° + MNO – 46° = 180° – 46°

MNO = 134°

Example v.5 Two angles are in the ratio 3:2. If they are linear pair, find them.

Solution

Permit the angles be threex and 2x

Since they are linear pair of angles, their sum is 180°.

Therefore, 3x+2x = 180°

5x = 180°

x = 180º / 5

10 = 36°

The angles are 310 = 3×36 = 108°

ii10 = 2×36 = 72°

More on linear pairs

Amudhan asked his instructor what would happen if he drew a ray in between a linear pair of angles? The teacher told him to draw it. Amudhan drew the ray as shown in Fig.5.8.

Teacher asked Amudhan, "what can you say about the angles AOB and BOC?". He said that they are side by side angles. Also information technology is true that AOB + BOC = AOC.


The teacher besides asked about the pair of angles AOC and COD . He replied that they are linear pair. Therefore, their sum is 180° i.e. AOC + COD = 180°.

Combining these two results we become AOB + BOC + COD = 180°.

Thus, the sum of all the angles formed at a point on a straight line is 180°.

Think

What would happen to the angles if nosotros add 3 or 4 or 5 rays on a line as given below?


We can learn i more result on linear pairs.

Observe the post-obit Fig.5.ix.

AB is a directly line. OC is a ray meeting AB at O .

Here, AOC and BOC are linear pair.

Hence AOC + BOC = 180°


Besides, OD is another ray coming together AB at O .

Again AOD and BOD are linear pair.

Hence AOD + BOD = 180°

Now, AOC , BOC , AOD and BOD are the angles that are formed at the point O .

We tin can observe that ( AOC + BOC ) + ( AOD + BOD ) = 180° + 180° = 360°.

So, the sum of the angles at a signal is 360°.

Think

Tin y'all justify the post-obit statement.

AOB + BOC + COD + DOE + EOF + FOA = 360°?


Example 5.6 From Fig.5.10, detect the measure of ROS .

Solution

We know that QOR + ROS + SOP = 180°


 26° + ROS + 32° = 180°

ROS + 58° = 180°

 Subtracting 58° on both sides

 Nosotros go, ROS = 180° – 58° = 122°

Example 5.7 In Fig. 5.11, notice the value of x °

Solution

98° + 23° + 76° + 10° = 360°


 197° + x° = 360°

 x ° = 360° − 197° = 163°

3. Vertically opposite angles

Nosotros have already studied almost intersecting lines. Observe the Fig.v.12. At that place are two lines namely l and g which are intersecting at a indicate O and forming 4 angles at that betoken of intersection. They are 1, ii, 3 and iv.


Consider any one angle among this say 1. The angles which are side by side to 1 are 2 and 4, 3 is a non-next bending. Similarly, for the remaining three angles two angles will exist adjacent and one bending will be non-adjacent. Nosotros can discover that an angle and its non-adjacent angle are simply opposite to each other at the point of intersection O (vertex). Such angles which are opposite to each other with reference to the vertex are called vertically opposite angles.

When two lines intersect each other, 2 pairs of not-side by side angles formed are called vertically opposite angles.

Try these

one. Four existent life examples for vertically reverse angles are given below.


Give four more examples for vertically contrary angles in your surrounding.


2. In the given effigy, two lines and intersect at O. Notice the pair of angles and complete the following table. One is done for you.



iii. Name the two pairs of vertically  opposite angles.


PTS and RTQ

PTR and STQ

4. Notice the value of x° in the figure given below.


10 o = 150o

Activity

On a paper draw ii intersecting lines  and . Let the two lines intersect at O . Label the two pairs of vertically opposite angles as ane, 2 and 3, 4. Make a trace of angles 2 and 3. Place the traced bending 2 on angle 1. Are they equal? Place the traced angle iii on angle 4. Are they equal? Continue the same for 5 different pair of intersecting lines. Record your observations and discuss.

Tags : Geometry | Term 1 Affiliate 5 | seventh Maths , 7th Maths : Term 1 Unit 5 : Geometry

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7th Maths : Term 1 Unit five : Geometry : Pair of Angles formed past Intersecting Lines | Geometry | Term i Affiliate 5 | 7th Maths

Angles Formed By Intersecting Lines,

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